If it's not what You are looking for type in the equation solver your own equation and let us solve it.
D( x )
x = 0
x = 0
x = 0
x in (-oo:0) U (0:+oo)
(x+1/x)^2-(5*(x+1/x))+6 = 0
(x+1/x)^2-5*(x+1/x)+6 = 0
(x+x^-1)^2-5*(x+x^-1)+6 = 0
(x+x^-1)^2-5*(x+x^-1)+6 = 0
x^2-5*x-5*x^-1+x^-2+2+6 = 0
x^2-5*x-5*x^-1+x^-2+8 = 0
x^2-5*x-5*x^-1+x^-2+8 = 0
1*x^2-5*x^1-5*x^-1+1*x^-2+8*x^0 = 0
(1*x^4-5*x^3+8*x^2-5*x^1+1*x^0)/(x^2) = 0 // * x^4
x^2*(1*x^4-5*x^3+8*x^2-5*x^1+1*x^0) = 0
x^2
x^4-5*x^3+8*x^2-5*x+1 = 0
{ 1, -1 }
1
x = 1
x^4-5*x^3+8*x^2-5*x+1 = 0
1
x-1
x^3-4*x^2+4*x-1
x^4-5*x^3+8*x^2-5*x+1
x-1
x^3-x^4
8*x^2-4*x^3-5*x+1
4*x^3-4*x^2
4*x^2-5*x+1
4*x-4*x^2
1-x
x-1
0
x^3-4*x^2+4*x-1 = 0
{ 1, -1 }
1
x = 1
x^3-4*x^2+4*x-1 = 0
1
x-1
x^2-3*x+1
x^3-4*x^2+4*x-1
x-1
x^2-x^3
4*x-3*x^2-1
3*x^2-3*x
x-1
1-x
0
x^2-3*x+1 = 0
DELTA = (-3)^2-(1*1*4)
DELTA = 5
DELTA > 0
x = (5^(1/2)+3)/(1*2) or x = (3-5^(1/2))/(1*2)
x = (5^(1/2)+3)/2 or x = (3-5^(1/2))/2
x in { (3-5^(1/2))/2, (5^(1/2)+3)/2, 1, 1}
(x-((3-5^(1/2))/2))*(x-((5^(1/2)+3)/2))*(x-1)^2 = 0
(x-((3-5^(1/2))/2))*(x-((5^(1/2)+3)/2))*(x-1)^2 = 0
( x-((3-5^(1/2))/2) )
x-((3-5^(1/2))/2) = 0 // + (3-5^(1/2))/2
x = (3-5^(1/2))/2
( x-((5^(1/2)+3)/2) )
x-((5^(1/2)+3)/2) = 0 // + (5^(1/2)+3)/2
x = (5^(1/2)+3)/2
( x-1 )
x-1 = 0 // + 1
x = 1
x in { (3-5^(1/2))/2, (5^(1/2)+3)/2, 1, 1 }
| 5/6x+1+3 | | 3j-7j=12 | | (x-9)(5x+12)=0 | | 121=r^2 | | 625=r^2 | | 324=r^2 | | 2x+5=3+5x | | 6-5=4x+1 | | 6x+5=4x+1 | | 5805.86=3.14r^2 | | 4j-9j+3=-3 | | (x-7)(y-5)= | | (5x)=(3x+28) | | (3x-1)(3-8x)= | | y=4(7x+100) | | y=1/2+5(0,3) | | (8k-9)(3k-7)= | | 36^1/2 | | x-49=57 | | 9x+6x-12=-7x+2x-12+5 | | -21=y/4 | | 9x-6=3x+6 | | -b=19 | | 6-3x=-5x-2 | | 2x-3x=3-x | | a-16/18=8/9 | | 1/6(5x-9)=7 | | 7-x=6+14 | | 8-4=x+1 | | 6x+4x=10 | | y=x^2*ln(x+2) | | 15x+3y=39 |